The purpose of this exercise is to tour the table and graphics capabilities of R, and to explore methods for displaying patterns in data. If you need help with some of the commands, check the “Graphs & Tables” tab at the R tips page.

You can draw plots using commands in base R or use ggplot() from the tidyverse. Each option has passionate adherents and it is pointless to argue. Try both and see which you find most appealing and easiest to use.


Data set 1: Mammal body mass

These data were published as a data paper in Ecology and deposited in the Ecological Archives (F. A. Smith, S. K. Lyons, S. K. M. Ernest, K. E. Jones, D. M. Kaufman, T. Dayan, P. A. Marquet, J. H. Brown, and J. P. Haskell. 2003. Body mass of late Quaternary mammals. Ecology 84: 3403.) See the metadata for a description.

Most of the variables are categorical, with multiple named categories. continent includes mammals on islands (“Insular” category) whereas “Oceanic” refers to marine mammals. Body mass (in grams) is the sole numeric variable. The status variable indicates whether species is currently present in the wild (extant), extinct as of late Pleistocene (extinct), extinct within the last 300 years (historical), or an introduced species (introduction).


Read and examine the data

The original data were saved in mammals.csv file on our server here. Download the file to your computer and open in a spreadsheet program (e.g., Excel, Calc) to have a look at it.

Start R and read the contents of the file to a data frame. You will need to modify the default argument that identifies missing data to na.strings=““ (or na=”“ if you are using read_csv() from the readr package) because in this data file”NA” is used to symbolize North America in the continent column rather than missing data (don’t do this in your own data).

Use the head() function to view the first few lines of the data frame on the screen. You’ll see that every row represents the data for a different mammal species.


Frequency tables

  1. Which continent has the greatest number of mammal species? Which has the least? Make a table of the frequency of cases on each continent (remember that the category “NA” in continent stands for North America, not missing data).

  2. You’ll notice in the frequency table for the variable continent that there’s a typo in the data. One case is shown as having the continent “Af” rather than “AF”. Fix this using the command line in R and recalculate the frequency table.

  3. How many extinct mammals are recorded in the data file? Use a frequency table to find out.

  4. Create a two-way frequency table (contingency table) showing the status of mammal species on each continent.

  5. Judging by eye, which continent has the greatest number of extinctions relative to the number of extant species?

Answers

All lines below beginning with double hashes are R output

# Load the packages you might need

library(readr)
library(dplyr)

# Read and inspect the data
mammals <- read.csv(url("https://www.zoology.ubc.ca/~bio501/R/data/mammals.csv"), 
                    na.strings="", stringsAsFactors = FALSE)
head(mammals)
##   continent status        order  family      genus       species mass.grams
## 1        AF extant Artiodactyla Bovidae      Addax nasomaculatus    70000.3
## 2        AF extant Artiodactyla Bovidae  Aepyceros      melampus    52500.1
## 3        AF extant Artiodactyla Bovidae Alcelaphus    buselaphus   171001.5
## 4        AF extant Artiodactyla Bovidae Ammodorcas       clarkei    28049.8
## 5        AF extant Artiodactyla Bovidae Ammotragus        lervia    48000.0
## 6        AF extant Artiodactyla Bovidae Antidorcas   marsupialis    39049.9

You could also use read_csv() from the readr package (not run).

mammals <- read_csv(url("https://www.zoology.ubc.ca/~bio501/R/data/mammals.csv"), 
                   na = c(""))

Number of mammal species on each continent

table(mammals$continent)
## 
##      Af      AF     AUS      EA Insular      NA Oceanic      SA 
##       1    1033     346    1033    1484     779      78     977
# Fix "Af"
which(mammals$continent=="Af")
## [1] 322
mammals$continent[322]<-"AF"
table(mammals$continent)
## 
##      AF     AUS      EA Insular      NA Oceanic      SA 
##    1034     346    1033    1484     779      78     977

How many extinct mammals? The table shows that 242 species of mammal are listed as extinct.

z <- table(mammals$status)
z
## 
##       extant      extinct   historical introduction 
##         5388          242           84           17

Extinction status by continent (contingency table). Australia (AUS) seems to have the greatest number of extinct species relative to the total number. This might be easier to see if the row sums are included in the table.

# base R
mytab <- table(mammals$continent, mammals$status)
addmargins(mytab, margin = c(1,2), FUN = sum, quiet = TRUE)
##          
##           extant extinct historical introduction  sum
##   AF        1017      13          4            0 1034
##   AUS        261      45         23           17  346
##   EA        1027       0          6            0 1033
##   Insular   1405      29         50            0 1484
##   NA         700      78          1            0  779
##   Oceanic     78       0          0            0   78
##   SA         900      77          0            0  977
##   sum       5388     242         84           17 5731

You can also use dplyr and tidyr to make a contingency table (not run). The last step is optional and converts NA to zero.

# dplyr and tidyr method
library(tidyverse)
mytab <- summarize(group_by(mammals, continent, status), n = n())
mytab <- spread(mytab, status, n)
mutate(mytab, across(everything(), ~replace_na(., 0)))
## # A tibble: 7 × 5
## # Groups:   continent [7]
##   continent extant extinct historical introduction
##   <chr>      <int>   <int>      <int>        <int>
## 1 AF          1017      13          4            0
## 2 AUS          261      45         23           17
## 3 EA          1027       0          6            0
## 4 Insular     1405      29         50            0
## 5 NA           700      78          1            0
## 6 Oceanic       78       0          0            0
## 7 SA           900      77          0            0


Graphing frequency distributions

  1. Plot the number of mammal species on each continent using a simple bar graph. Include a label for the y axis.

  2. The plot categories are listed in alphabetical order by default, which is arbitrary and makes the visual display less efficient than other possibilities. Redo the bar graph with the continents appearing in order of decreasing numbers of species.

  3. Generate a histogram of the body masses of mammal species. How informative is that?!

  4. Create a new variable in the mammal data frame: the log (base 10) of body mass. (See “Transform” on the R tips “Data” page if you need help with this.)

  5. Generate a histogram of log body mass. Is this more informative? Morphological data commonly require a log-transformation to analyze.

  6. Redo the previous histogram but use a bin width of 2 units. How much detail is lost?

  7. Redo the histogram but try a bin width of of 1; then try 0.5; and then 0.1. Which bin width is superior?

  8. Redo the histogram, but display probability density instead of frequency.

  9. How does the frequency distribution of log body mass depart from a normal distribution? Answer by visual examination of the histogram you just created. Now answer by examining a normal quantile plot instead. Which display is more informative? Do the data conform to a normal distribution?

  10. Optional: redraw the histogram of log body mass and superimpose a normal density curve to help visualize deviations from normality. In what ways do the data depart from normality?

Answers

All lines below beginning with double hashes are R output

# Bar plot of mammal species by continent
barplot(table(mammals$continent), col="firebrick", cex.names=0.8, 
        ylim=c(0,1600), las = 1)

# Barplot sorted by frequency
barplot(sort(table(mammals$continent), decreasing=TRUE), col="firebrick",   
        cex.names=0.8, las = 1, ylim=c(0,1600), ylab="Frequency")

Alternatively, use ggplot() instead of base R.

library(ggplot2)
ggplot(mammals, aes(x = continent)) + 
    geom_bar(stat = "count", fill = "firebrick") +
    labs(x = "Continent", y = "Frequency") +
  theme_classic()

# To order by category in ggplot, first make a new factor variable
mammals$continent_ordered <- factor(mammals$continent, 
                levels = names(sort(table(mammals$continent), decreasing = TRUE)) )

ggplot(mammals, aes(x = continent_ordered)) + 
    geom_bar(stat = "count", fill = "firebrick") +
    labs(x = "Continent", y = "Frequency") +
  theme_classic()

Histogram of body masses. Results with different bin widths not shown

hist(mammals$mass.grams, col="firebrick", right = FALSE, las = 1, 
     xlab = "Body mass (g)", main = "")

# Add a new variable, log10 of body mass
mammals$logmass <- log10(mammals$mass.grams)

hist(mammals$logmass, col="firebrick", right = FALSE, las = 1, 
     xlab = "Log10 body mass", main = "", breaks = seq(0, 8.5, by = 0.5))

Same but using ggplot(). You’ll see a Warning: Removed ?? rows containing non-finite values. These are rows with missing data for mass. Use the argument na.rm = TRUE in geom_histogram() to get rid of the warning.

ggplot(mammals, aes(x = logmass)) + 
    geom_histogram(fill = "firebrick", col = "black", binwidth = 0.5, boundary = 0) + 
    labs(x = "log10 body mass", y = "Frequency") + 
    theme_classic()
## Warning: Removed 1372 rows containing non-finite values (`stat_bin()`).

Plot density instead

hist(mammals$logmass, col = "firebrick", right = FALSE, las = 1, prob = TRUE,
     xlab = "Log10 body mass", main = "", breaks = seq(0, 8.5, by = 0.5))

or

ggplot(mammals, aes(x = logmass)) + 
    geom_histogram(fill = "firebrick", col = "black", binwidth = 0.5, 
                 boundary = 0, aes(y = after_stat(density))) + 
    labs(x = "log10 body mass", y = "Density") + 
  theme_classic()
## Warning: Removed 1372 rows containing non-finite values (`stat_bin()`).

Normal quantile plot.

qqnorm(mammals$logmass)
qqline(mammals$logmass) # adds the straight line for comparison through 1st and 3rd quartiles

Histogram with best-fit normal curve superimposed.

# The curve function is fussy about the name of the variable: must be "x"
x <- mammals$logmass
hist(x, col="firebrick", right = FALSE, las = 1, prob = TRUE,
     xlab = "Log10 body mass", main = "", breaks = seq(0, 8.5, by = 0.5))
m <- mean(x, na.rm = TRUE)
s <- sd(x, na.rm = TRUE)
curve(dnorm(x, mean = m, sd = s), col="red", lwd = 2, add = TRUE)


Comparing frequency distributions

  1. Use a box plot to compare the distribution of body sizes (log scale most revealing) of mammals having different extinction status. Are extinct mammals similar to, larger than, or smaller than, extant mammals?

  2. Examine the previous box plot. How do the shapes of the body size distributions compare between extinct and extant mammals?

  3. Redo the previous box plot but make box width proportional to the square root of sample size. Add a title to the plot.

  4. Optional: Draw a violin plot to compare the frequency distribution of log body sizes of mammals having different extinction status. Which do you find is more revealing about the shapes of the body size distributions: box plot or violin plot?

  5. Use multiple histograms to compare the frequency distribution of log body sizes of mammals having different extinction status. Stack the panels one above the other. In this plot, how easy is it to visualize differences among treatments in the distributions compared to your previous plots?

  6. Make a table of the median log body mass of each extinction-status group of mammals. Are the values consistent with the plotted distributions?

Answers

All lines below beginning with double hashes are R output

The graphs show that Extinct mammals tend to have large mass compared to extant mammals. The frequency distributions for these two groups also have opposite skew, with extinct mammals having left skew.

# Base R box plot to compare the distribution of body sizes
boxplot(logmass ~ status, data = mammals, ylab = "log10 body mass", 
        col = "goldenrod1", las = 1)

or

ggplot(mammals, aes(x = status, y = logmass)) + 
    geom_boxplot(fill = "goldenrod1", notch = FALSE) + 
    labs(x = "Status", y = "Log10 body mass") + 
    theme_classic()
## Warning: Removed 1372 rows containing non-finite values (`stat_boxplot()`).

# Violin plot
ggplot(mammals, aes(x = status, y = logmass)) + 
    geom_violin(fill = "goldenrod1") + 
    labs(x = "Status", y = "Log10 body mass") + 
    stat_summary(fun = mean,  geom = "point", color = "black") +
  theme_classic()
## Warning: Removed 1372 rows containing non-finite values (`stat_ydensity()`).
## Warning: Removed 1372 rows containing non-finite values (`stat_summary()`).

# Multiple histograms
ggplot(mammals, aes(x = logmass)) + 
    geom_histogram(fill = "goldenrod1", col = "black", 
             binwidth = 0.2, boundary = 0) +
    labs(x = "log10 body mass", y = "Frequency") + 
    facet_wrap(~status, ncol = 1, scales = "free_y", strip.position = "right") +
  theme_classic()
## Warning: Removed 1372 rows containing non-finite values (`stat_bin()`).


Data set 2: Fly sex and longevity

The data are from L. Partridge and M. Farquhar (1981), Sexual activity and the lifespan of male fruitflies, Nature 294: 580-581. The experiment placed male fruit flies with varying numbers of previously-mated or virgin females to investigate how mating activity affects male lifespan. The data are in the file fruitflies.csv file on our server here.


Download and inspect

Download the file to your computer and open in a spreadsheet program to have a look at it. View the first few lines of the data frame on the screen, and familiarize yourself with the variable names.

Our goal here is to find a plot type that clearly and efficiently visualizes the patterns in the data, especially the differences among groups.


Analyze

  1. Read the data file into a new data frame.

  2. Use a strip chart to examine the distribution of longevities in the treatment groups. Try the jitter method to reduce overlap between points. If needed, adjust the size or rotation of the treatment labels so that they all fit on the graph. What pattern of differences between treatments in longevity is revealed? Males from which treatments have the highest longevity? Which have the lowest longevity?

  3. Compare the strip chart to a box plot of the same data. Is the pattern in the data as clear in both types of plot?

  4. The variable thorax stands for thorax length, which was used as a measure of body size. The measurement was included in case body size also affected longevity. Using ggplot(), produce a scatter plot of thorax length and longevity. Make longevity the response variable (i.e., plot it on the vertical axis). Is there a relationship?

  5. Redraw the scatter plot using ggplot() but this time use different symbols and/or colors for the different treatment groups. Add a legend to identify the symbols. After controlling for differences among males in size, males from which treatments have the highest longevity on average? Which have the lowest longevity?

  6. Redraw, adding regression lines to your figure, separately for each group.

  7. You can see how it can be fiendishly difficult to build a clean visual showing the pattern in the data when there are multiple groups. Redraw the figure again using just one color and symbol, but this time use facet_wrap() to plot the data in multiple panels, one per treatment group. Compare your results with those from (6). Which method shows the differences between groups most clearly?

Answers

All lines below beginning with double hashes are R output

# Read and inspect data
x <- read.csv(url("https://www.zoology.ubc.ca/~bio501/R/data/fruitflies.csv"),
              stringsAsFactors = FALSE)
head(x)
##   Npartners          treatment longevity.days thorax.mm
## 1         8 8 pregnant females             35      0.64
## 2         8 8 pregnant females             37      0.68
## 3         8 8 pregnant females             49      0.68
## 4         8 8 pregnant females             46      0.72
## 5         8 8 pregnant females             63      0.72
## 6         8 8 pregnant females             39      0.76

Strip chart in base R.

stripchart(longevity.days ~ treatment, data = x, vertical = TRUE,  
                method = "jitter", pch=16, col = "firebrick", cex.axis=0.7, 
                ylab="Longevity (days)")

or using ggplot()

# Strip chart using ggplot
ggplot(x, aes(x = treatment, y = longevity.days)) +
    geom_jitter(color = "firebrick", size = 3, width = 0.15) +
    labs(x = "Treatment", y = "Longevity (days)") + 
    theme_classic()

Box plot.

boxplot(longevity.days ~ treatment, data = x, cex.axis = 0.7, 
    ylab = "Longevity (days)", boxwex = 0.5, col = "goldenrod1")

or using ggplot()

ggplot(x, aes(x = treatment, y = longevity.days)) +
    geom_boxplot(fill = "goldenrod1", width = 0.5) +
    labs(x = "Treatment", y = "Longevity (days)") + 
    theme_classic()

Scatter plot in base R.

plot(longevity.days ~ thorax.mm, data = x, pch = 16, col = "firebrick", las = 1,
     xlab = "Thorax length (mm)", ylab = "Longevity (days)")

or using ggplot()

# Scatter plot with ggplot
ggplot(x, aes(x = thorax.mm, y = longevity.days)) + 
    geom_point(size = 3, col = "firebrick") + 
    labs(x = "Thorax length (mm)", y = "Longevity (days)") + 
    theme_classic()

Scatter plot with separate colors for each group using ggplot()

ggplot(x, aes(x = thorax.mm, y = longevity.days, colour = treatment, 
            shape = treatment)) + 
    geom_point(size = 2) + 
    labs(x = "Thorax length (mm)", y = "Longevity (days)") + 
    theme_classic()

# Add lines
ggplot(x, aes(x=thorax.mm, y=longevity.days, colour = treatment, 
            shape = treatment)) + 
    geom_point(size = 2) +
    geom_smooth(method = lm, linewidth = 1, se = FALSE) +
    labs(x = "Thorax length (mm)", y = "Longevity (days)") + 
    theme_classic()
## `geom_smooth()` using formula = 'y ~ x'

Using facet_wrap() to plot treatment groups in separate panels.

ggplot(x, aes(x = thorax.mm, y = longevity.days)) + 
  facet_wrap(~ treatment, strip.position = "top") +
    geom_point(size = 2) +
    geom_smooth(method = lm, linewidth = 1, se = FALSE) +
    labs(x = "Thorax length (mm)", y = "Longevity (days)") + 
    theme_classic()
## `geom_smooth()` using formula = 'y ~ x'

Here’s how you would draw a scatter plot with separate colors and symbols for each group using base R.

plot(longevity.days ~ thorax.mm, data=x, pch=as.numeric(factor(treatment)), 
        col = as.numeric(factor(treatment)), las = 1, 
        xlab = "Thorax length (mm)", ylab = "Longevity (days)")
legend( locator(1), legend = as.character(levels(factor(x$treatment))),
        pch=1:length(levels(factor(x$treatment))), 
        col=1:length(levels(factor(x$treatment))) )
 

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